-x^2+54x+504=0

Solution for -x^2+54x+504=0 equation:

-x^2+54x+504=0

We add all the numbers together, and all the variables

-1x^2+54x+504=0

a = -1; b = 54; c = +504;
Δ = b2-4ac
Δ = 542-4·(-1)·504
Δ = 4932
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4932}=\sqrt{36*137}=\sqrt{36}*\sqrt{137}=6\sqrt{137}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-6\sqrt{137}}{2*-1}=\frac{-54-6\sqrt{137}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+6\sqrt{137}}{2*-1}=\frac{-54+6\sqrt{137}}{-2}
$